Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
0 votes

In how many ways can a team of 3boys and 3 girls be selected from 5 boys and 4 girls?

$\begin{array}{1 1}(A)\;20\\(B)\;30\\(C)\;40\\(D)\;50\end{array} $

Can you answer this question?

1 Answer

0 votes
  • $C(n,r)=\large\frac{n!}{r!(n-r)!}$
3 boys out of 5 boys can be selected in =$5C_3$ ways
3 girls out of 4 boys can be selected in =$4C_3$ ways
Number of boys in which 3 boys and 3 girls are selected are
$5C_3\times 4C_3=5C_2\times 4C_1$
$\Rightarrow \large\frac{5\times 4}{1\times 2}\times \frac{4}{1}$
$\Rightarrow \large\frac{20\times 4}{2}$$=40$
Hence (C) is the correct answer.
answered May 14, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App