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In how many ways can a student choose a programme of 5 courses if 9 courses are available and 2 courses are compulsory for every student.

$\begin{array}{1 1}(A)\;30\\(B)\;32\\(C)\;34\\(D)\;35\end{array} $

1 Answer

Out of available nine courses,two are compulsory.Hence the student is free to select 3 courses out of 7 remaining courses.If P is the number of ways of selecting 3 courses out of 7 courses,then
$P=C(7,3)$
$\;\;\;=\large\frac{7!}{3!(7-3)!}$
$\;\;\;=\large\frac{7!}{3!4!}$
$\;\;\;=\large\frac{7\times 6\times 5\times 4!}{3\times 2\times 1\times 4!}$
$\;\;\;=35$ ways
Hence (D) is the correct answer.
answered May 14, 2014 by sreemathi.v
 

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