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Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
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In how many ways can a student choose a programme of 5 courses if 9 courses are available and 2 courses are compulsory for every student.

$\begin{array}{1 1}(A)\;30\\(B)\;32\\(C)\;34\\(D)\;35\end{array} $

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Out of available nine courses,two are compulsory.Hence the student is free to select 3 courses out of 7 remaining courses.If P is the number of ways of selecting 3 courses out of 7 courses,then
$\;\;\;=\large\frac{7\times 6\times 5\times 4!}{3\times 2\times 1\times 4!}$
$\;\;\;=35$ ways
Hence (D) is the correct answer.
answered May 14, 2014 by sreemathi.v

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