Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
0 votes

A committee of 7 has to be formed from 9 boys and 4 girls.In how many ways can this be done when the committee consists of Exactly 3 girls?

$\begin{array}{1 1}(A)\;500\\(B)\;502\\(C)\;504\\(D)\;505\end{array} $

Can you answer this question?

1 Answer

0 votes
  • $C(n,r)=\large\frac{n!}{r!(n-r)!}$
A committee consisting of 3 girls and 4 boys can be formed in $1C_3\times 9C_4$ ways
$\Rightarrow 4C_1\times 9C_4$
$\Rightarrow \large\frac{4}{1}\times \frac{9\times 8\times 7\times 6}{}$
$\Rightarrow 504$ ways
Hence (C) is the correct answer.
answered May 14, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App