$\begin{array}{1 1}(A)\;2660\\(B)\;2770\\(C)\;2880\\(D)\;2990\end{array} $

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- $n!=n(n-1)(n-2).....(3)(2)(1)$

According to the problem women will sit at the even places (2,4,6 and 8).

They can be seated in P(4,4)=4!=24 ways

Men will sit on the odd seats =(1,3,5,7 & 9 ways)

They can sit on these seats in

$P(5,5)=5!$

$\Rightarrow 5\times 4\times 3\times 2\times 1$

$\Rightarrow 120$ ways

If total number of ways P then

$P=24\times 120$

$\;\;\;=2880$

Hence (C) is the correct answer.

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