According to the problem women will sit at the even places (2,4,6 and 8).
They can be seated in P(4,4)=4!=24 ways
Men will sit on the odd seats =(1,3,5,7 & 9 ways)
They can sit on these seats in
$\Rightarrow 5\times 4\times 3\times 2\times 1$
$\Rightarrow 120$ ways
If total number of ways P then
Hence (C) is the correct answer.