$\begin{array}{1 1}(A)\;151200\\(B)\;152200\\(C)\;153200\\(D)\;154200\end{array} $

- $n!=n(n-1)(n-2)(n-3).......(3)(2)(1)$
- $C[(n,r)]=\large\frac{n!}{r!(n-r)!}$

The word ASSASSINATION has 4S,3A,2I,2N,T,O,4S are together.

This is considered as one block as 1 letter

Now we have 3A,2I,2N,4S,T,O

$\Rightarrow \large\frac{10!}{3!2!2!}=\frac{10\times 9\times 8\times 7\times 6\times 5\times 4\times 3\times 2\times 1}{(3\times 2\times 1)\times (2\times 1)\times (2\times 1)}$

$\Rightarrow 10\times 9\times 8\times 7\times 5\times 3\times 2$

$\Rightarrow 151200$

Hence (A) is the correct answer.

Ask Question

Tag:MathPhyChemBioOther

Take Test

...