$\begin{array}{1 1}(A)\;3940\\(B)\;3950\\(C)\;3960\\(D)\;3970\end{array} $

The chair person can be selected in =12 ways

The ways of selecting the other 4 members=$11C_4$

$\Rightarrow 11C_4=\large\frac{11!}{4!\times 7!}$

$\Rightarrow \large\frac{11\times 10\times 9\times 8\times 7!}{4\times 3\times 2 \times 1\times 7!}$

$\Rightarrow 110\times 3$

$\Rightarrow 330$

No of ways of selecting 5 member of the committee=$330\times 12$

$\Rightarrow 3960$

Hence (C) is the correct answer.

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