$\begin{array}{1 1}(A)\;2\\(B)\;3\\(C)\;4\\(D)\;5\end{array} $

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Total no of questions =5

Total no of questions to be answered =4

Compulsory questions =1 and 2

Hence the remaining questions are

Hence the no of ways a student can make choice =$3C_2$

$\Rightarrow \large\frac{3!}{2!\times 1!}$

$\Rightarrow \large\frac{3\times 2!}{2!}$

$\Rightarrow 3$

Hence (B) is the correct answer.

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