logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
0 votes

In an examination a student has to answer 4 questions out of 5 questions;questions 1 and 2 are compulsory.Determine the number of ways in which the student can make choice.

$\begin{array}{1 1}(A)\;2\\(B)\;3\\(C)\;4\\(D)\;5\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Total no of questions =5
Total no of questions to be answered =4
Compulsory questions =1 and 2
Hence the remaining questions are
Hence the no of ways a student can make choice =$3C_2$
$\Rightarrow \large\frac{3!}{2!\times 1!}$
$\Rightarrow \large\frac{3\times 2!}{2!}$
$\Rightarrow 3$
Hence (B) is the correct answer.
answered May 15, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...