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Permutations and Combinations
In how many ways can a football team of 11 players be selected from 16 players?How many of them will exclude 2 particular players?
$\begin{array}{1 1}(A)\;14C_{9}\\(B)\;14C_{11}\\(C)\;16C_{11}\\(D)\;11C_9\end{array} $
cbse
math
class11
ch7
permutations-and-combinations
exercise7-3
exemplar
q23-b
sec-b
medium
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asked
May 15, 2014
by
sreemathi.v
edited
May 10, 2016
by
meena.p
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1 Answer
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$C(n,r)=\large\frac{n!}{r!(n-r)!}$
Total no of players =16
Since 2 particular players are excluded from every selection.So we have to select 11 players from the remaining 14 players
This can be done in -$14C_{11}$ ways
Hence (B) is the correct answer.
answered
May 15, 2014
by
sreemathi.v
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