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In how many ways can a football team of 11 players be selected from 16 players?How many of them will exclude 2 particular players?

$\begin{array}{1 1}(A)\;14C_{9}\\(B)\;14C_{11}\\(C)\;16C_{11}\\(D)\;11C_9\end{array} $

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  • $C(n,r)=\large\frac{n!}{r!(n-r)!}$
Total no of players =16
Since 2 particular players are excluded from every selection.So we have to select 11 players from the remaining 14 players
This can be done in -$14C_{11}$ ways
Hence (B) is the correct answer.
answered May 15, 2014 by sreemathi.v

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