$\begin{array}{1 1}(A)\;216\\(B)\;600\\(C)\;240\\(D)\;3125\end{array} $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

- $n!=n(n-1)(n-2)(n-3).......(3)(2)(1)$

1+2+3+4+5=15 divisible by 3

The no of five digit numbers formed =5! ways

$\Rightarrow 120$ ways

The no of five digit numbers that can be formed using 0,1,2,3,4 can be

First digit $\rightarrow 4$ways

Second digit $\rightarrow 4$ways

Third digit $\rightarrow 3$ways

Fourth digit $\rightarrow 2$ways

Fifth digit $\rightarrow 1$way

Total no of ways =$4\times 4\times 3\times 2\times 1$

$\Rightarrow 4\times 4!$

$\Rightarrow 96$

Hence total number of ways =$120+96$

$\Rightarrow 216$

Hence (A) is the correct answer.

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...