Total no of consonants =6
Total no of vowels =6
Total no of letters in the word INTERMEDIATE =12
No of ways of arranging the consonants of which two are alike =$\large\frac{6!}{2!}$
$\Rightarrow \large\frac{6\times 5\times 4\times 3\times 2}{2}$
$\Rightarrow 360$
No of ways of arranging the vowels =$7P_6\times \large\frac{1}{3!}\times \frac{1}{2!}$
$\Rightarrow \large\frac{7!}{1!}\times \frac{1}{3!}\times \frac{1}{2!}$
$\Rightarrow \large\frac{7\times 6\times 5\times 4\times 3!}{3!\times 2}$
$\Rightarrow 420$
Total no of ways =$420\times 360$
$\Rightarrow 151200$
Hence (A) is the correct answer.