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Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
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The number of six digit numbers,all digits of which are odd is

$\begin{array}{1 1}(A)\;6^5\\(B)\;5^6\\(C)\;5^4\\(D)\;5^2\end{array} $

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Total no of odd digits between 0-9 are =$1,3,5,7,9$
Hence there are 5 digits
The total no of six digit no =$5^6$
$\Rightarrow 15,625$
Hence (B) is the correct answer.
answered May 16, 2014 by sreemathi.v

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