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There are 3 books on mathematics 4 on physics and 5 on english .How many different collections can be made such that each collections consists of : one book of each subject

$\begin{array}{1 1}(A)\;40\\(B)\;50\\(C)\;60\\(D)\;70\end{array} $

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  • $C(n,r)=\large\frac{n!}{r!(n-r)!}$
Mathematics =3
Physics =4
English =5
One look of each subject =$3\times 4\times 5$
$\Rightarrow 60$
Hence (C) is the correct answer.
answered May 19, 2014 by sreemathi.v

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