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There are 3 books on mathematics 4 on physics and 5 on english .How many different collections can be made such that each collections consists of : Atleast one book of english

$\begin{array}{1 1}(A)\;3968\\(B)\;3155\\(C)\;3355\\(D)\;3255\end{array} $

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All ways =$2^3\times 2^4\times 2^5$
No of ways with at least one book of english =$2^3\times 2^4\times 2^5-2^3\times 2^4$
$\Rightarrow 3968$
Hence (A) is the correct answer.
answered May 19, 2014 by sreemathi.v

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