logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
0 votes

Five boys and five girls form a line.Find the number of ways of making the seating arrangement under the following condition : Boys and girls alternate

$\begin{array}{1 1}(A)\;(5!)^2+(5!)^2\\(B)\;(2!)^2+(2!)^2\\(C)\;(3!)^2+(3!)^2\\(D)\;\text{None of these}\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
No of ways the girls can sit =5!
No of ways the boys can sit =5!
Boys and girls alternate =$5!\times 5!$
Vice versa =$5!\times 5!$
$\Rightarrow (5!)^2+(5!)^2$
Hence (A) is the correct answer.
answered May 19, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...