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There are 10 professors and 20 lecturers out of whom a committee of 2 professors and 3 lecturers is to be formed. In how many ways can a committee be formed?

$\begin{array}{1 1}(A)\;20C_3\times 10C_2\\(B)\;10C_3\times 5C_2\\(C)\;15C_3\times 5C_2\\(D)\;\text{None of these}\end{array} $

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  • $C(n,r)=\large\frac{n!}{r!(n-r)!}$
The no of ways the committee can be formed =$20C_3\times 10C_2$
Hence (A) is the correct answer.
answered May 19, 2014 by sreemathi.v
 

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