$\begin{array}{1 1}(A)\;40\\(B)\;25\\(C)\;50\\(D)\;75\end{array} $

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The no.divisible by 25 should end with 5

Thus the last two digit should be 25 or 75 for other 2 digit no. we have =$5P_2$

$\Rightarrow \large\frac{5!}{3!}$

$\Rightarrow \large\frac{5\times 4\times 3!}{3!}$

$\Rightarrow 20$

Hence if the last two digit is 75

The no. of ways will be 20

Thus the total no. of way =20+20

$\Rightarrow 40$

Hence (A) is the correct answer.

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