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Using the digits 1,2,3,4,5,6,7,a number of 4 different digit is formed.Find (d) How many of these are exactly divisible by 4

$\begin{array}{1 1}(A)\;10P_2\times 5P_2\\(B)\;11P_2\times 5P_2\\(C)\;9P_2\times 4P_2\\(D)\;8P_2\times 3P_2\end{array} $

1 Answer

If the last two digit is divisible by 4
1,2,3,4,5,6,7
The no. divisible by 4 are 12,24,32,44,52,64,72,16,36,56,76
$11P_2\times 5P_2$
Hence (B) is the correct answer.
answered May 19, 2014 by sreemathi.v
 

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