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The number of arrangements of letters of the word BANANA in which the two N's do not appear adjointly is

$\begin{array}{1 1}(A)\;40\\(B)\;60\\(C)\;80\\(D)\;100\end{array} $

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Total no of words BANANA =6
Total no of arrangement =$\large\frac{6!}{3!2!}$
$\Rightarrow 60$
No of words in which two N are together =$\large\frac{5!}{3!}$
$\Rightarrow 20$
$\therefore$ No of words in which two N are no together=$60-20$
$\Rightarrow 40$
Hence (A) is the correct answer.
answered May 19, 2014 by sreemathi.v

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