logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
0 votes

The number of arrangements of letters of the word BANANA in which the two N's do not appear adjointly is

$\begin{array}{1 1}(A)\;40\\(B)\;60\\(C)\;80\\(D)\;100\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Total no of words BANANA =6
Total no of arrangement =$\large\frac{6!}{3!2!}$
$\Rightarrow 60$
No of words in which two N are together =$\large\frac{5!}{3!}$
$\Rightarrow 20$
$\therefore$ No of words in which two N are no together=$60-20$
$\Rightarrow 40$
Hence (A) is the correct answer.
answered May 19, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...