$\begin{array}{1 1}(A)\;160\\(B)\;125\\(C)\;224\\(D)\;175\end{array} $

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- $C(n,r)=\large\frac{n!}{r!(n-r)!}$

Total no of officers =4

Total no of jawan =8

Total no of committees =$4C_1\times 8C_5$

$4C_1=\large\frac{4!}{1!3!}$$=4$

$8C_5=\large\frac{8!}{5!3!}=\frac{8\times 7\times 6\times 5!}{5!\times 3\times 2}$$=56$

$\Rightarrow 4\times 56$

$\Rightarrow 224$

Hence (C) is the correct answer.

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