$\begin{array}{1 1}(A)\;90000\\(B)\;100000\\(C)\;30240\\(D)\;69760\end{array} $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

- $n!=n(n-1)(n-2)(n-3)......(3)(2)(1)$

No of numbers with repetition =$10\times 10\times 10\times 10\times 10$

$\Rightarrow 100000$

No.of numbers without repetition =$10\times 9\times 8\times 7\times 6$

$\Rightarrow 30240$

$\therefore$ No.of numbers with atleast one digit repeated =$10,0000-30240$

$\Rightarrow 69760$

Hence (D) is the correct answer.

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...