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Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
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If letters of the word 'KUBER' are written in all possible orders and arranged as in a dictionary,then rank of the word 'KUBER' will be

$\begin{array}{1 1}(A)\;67\\(B)\;68\\(C)\;65\\(D)\;69\end{array} $

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1 Answer

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$n!=n(n-1)(n-2)(n-3).....(3)(2)(1)$
Total words starting with B=4!=24
Total words starting with E=4!=24
Total words starting with KB=3!=6
Total words starting with KE=3!=6
Total words starting with KR=3!=6
Start word will be KUBER
That rank of the word KUBER is 24+24+18+1=67
Hence (A) is the correct answer.
answered May 19, 2014 by sreemathi.v
 

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