logo

Ask Questions, Get Answers

X
 
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations

If letters of the word 'KUBER' are written in all possible orders and arranged as in a dictionary,then rank of the word 'KUBER' will be

$\begin{array}{1 1}(A)\;67\\(B)\;68\\(C)\;65\\(D)\;69\end{array} $

1 Answer

$n!=n(n-1)(n-2)(n-3).....(3)(2)(1)$
Total words starting with B=4!=24
Total words starting with E=4!=24
Total words starting with KB=3!=6
Total words starting with KE=3!=6
Total words starting with KR=3!=6
Start word will be KUBER
That rank of the word KUBER is 24+24+18+1=67
Hence (A) is the correct answer.
answered May 19, 2014 by sreemathi.v
 

Related questions

...