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The number of possible outcomes in a throw of n ordinary dice in which atleast one of the dice shows and odd number is

$\begin{array}{1 1}(A)\;6^n-1\\(B)\;3^n-1\\(C)\;6^n-3^n\\(D)\;\text{None of these}\end{array} $

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Total number of ways =$6\times 6\times......$ to n times
$\Rightarrow 6^n$
Total number of ways to show only even numbers =$3\times 3\times 3.....$ to n times
$\Rightarrow 3^n$
Hence (D) is the correct answer.
answered May 19, 2014 by sreemathi.v

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