$(a)\;\large\frac{L}{2}-\large\frac{\lambda_{0}L^{2}}{4M} \qquad(b)\;\large\frac{L}{3}+\large\frac{\lambda_{0}L^{2}}{8M}\qquad(c)\;\large\frac{L}{3}+\large\frac{\lambda_{0}L^{2}}{4M}\qquad(d)\;\large\frac{2L}{3}-\large\frac{\lambda_{0}L^{2}}{6M}$

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