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# The number of different matrices that can be formed with elements 0,1,2 or 3 each matrix having 4 elements ,is

$\begin{array}{1 1}(A)\;3\times 2^4\\(B)\;2\times 4^4\\(C)\;3\times 4^4\\(D)\;\text{None of these}\end{array}$

Tha matrix will be of the order =$4\times 1$ or $1\times 4$ or $2\times 2$
For each order,the number of different matrices =The number of ways to fill four places by=0,1,2,3
$\Rightarrow 4\times 4 \times 4\times 4$
Hence (D) is the correct answer.
we have 3 possible order of matrices,
and no. of different matrices =4^4
so answer will be =3 * 4^4 .