# Which of the following is correct?

$\begin{array}{1 1}(A)\;\sin 1^{\large\circ} > \sin 1&(B)\;\sin 1^{\large\circ} < \sin 1\\(C)\;\sin 1^{\large\circ} = \sin 1&(D)\;\sin 1^{\large\circ} =\large\frac{\pi}{18}\normalsize \sin 1\end{array}$

1 radian =$57^{\large\circ} 30'$ approx
$\therefore \sin \theta$ increase from $0^{\large\circ}$ to $180^{\large\circ}$
Hence (B) is the correct answer.