$\begin {array} {1 1} (A)\;x = \large\frac{5}{22} & \quad (B)\;x=-\large\frac{5}{22} \\ (C)\;y = \large\frac{5}{22} & \quad (D)\;y =- \large\frac{5}{22} \end {array}$

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- Equation of a line passing parallel to $y$ - axis is $x=a$, where $a$ is a constant.

Given equation of the two lines are

$ \qquad x-7y+5=0$

$ \qquad 3x+y=0$

On solving the two equations for $x$ and $y$ we get,

$ \qquad x-7(-3x)+5=0$

$ \qquad 22x+5=0 \Rightarrow x = - \large\frac{5}{22}$

and $y = \large\frac{15}{22}$

The point of intersection of the above two lines is $ \bigg( -\large\frac{5}{22}$$, \large\frac{15}{22} \bigg)$

Since the line $x=a$ passes through the point $ \bigg( -\large\frac{5}{22}$$, \large\frac{15}{22} \bigg)$

$ a = -\large\frac{5}{22}$

Hence the required equation of the line is

$ x = -\large\frac{5}{22}$

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