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Home  >>  CBSE XII  >>  Math  >>  Application of Derivatives

At what point in the interval $ [0,2\pi] $ does the function $\sin2x$ attain its maximum value?

1 Answer

Toolbox:
  • At maxima $ f\: ' (x) = 0$
Step 1
 
$ 2cos\: 2x = 0\: \Rightarrow x = \large\frac{\pi}{4}, \: \large\frac{3\pi}{4},\: \large\frac{5\pi}{4},\: \large\frac{7\pi}{4}$
Step 2
$ f \:" (x) = -4sin\: 2x$ is negative when $ x = \large\frac{\pi}{4}, \: \large\frac{5\pi}{4}$
Ans : At $ x = \large\frac{\pi}{4}\: and \: \large\frac{5\pi}{4}\: f(x)$ attains maximum value.

 

answered Apr 13, 2013 by thanvigandhi_1
 

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