Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Trigonometric Functions
0 votes

In right-angled triangle,the difference between the two acute angles is $(\large\frac{\pi}{15})^c$.Find the angles in degrees

$\begin{array}{1 1}(A)\;51^{\large\circ},39^{\large\circ},90^{\large\circ}\\(B)\;50^{\large\circ},40^{\large\circ},95^{\large\circ}\\(C)\;60^{\large\circ},40^{\large\circ},70^{\large\circ}\\(D)\;80^{\large\circ},50^{\large\circ},90^{\large\circ}\end{array} $

Can you answer this question?

1 Answer

0 votes
  • Degree measure =$\large\frac{180}{\pi}$$\times$ radian measure
The sum of the two acute angles of a right triangle is $90^{\large\circ}$
Difference between the actute angles
$\large\frac{\pi}{15}^c=(\frac{\pi}{15}\times \frac{180}{\pi})^{\large\circ}$
$\Rightarrow 12^{\large\circ}$
Let the two acute angles be $x^{\large\circ}$ and $y^{\large\circ}$ then,
$\Rightarrow y=39^{\large\circ}$
Hence the angles of a triangle are $51^{\large\circ},39^{\large\circ},90^{\large\circ}$
Hence (A) is the correct answer.
answered May 21, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App