logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The angular frequency of the damped oscillator is given by , $\;w=\sqrt{\large\frac{k}{m}-\large\frac{r^{2}}{4m^{2}}}\;$ where k is the spring constant , m is the mass of the oscillator and r is the damping constant.If the ratio $\;\large\frac{r^{2}}{mk}\;$ is $\;8\%\;$ , the change in time period compared to the undamped oscillator is approximately as follows :

$(a)\;increases\;by\;1\% \qquad(b)\;increases\;by\;8\%\qquad(c)\;decreases\;by\;1\%\qquad(d)\;decreases\;by\;8\%$

Can you answer this question?
 
 

Please log in or register to answer this question.

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...