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Questions  >>  CBSE XI  >>  Math  >>  Trigonometric Functions
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Q)

Solve the equation $\sin 9\theta=\sin \theta$

$\begin{array}{1 1}(A)\;\theta=\large\frac{n\pi}{4},\frac{(2n+1)\pi}{10}\\(B)\;\theta=\large\frac{n\pi}{6},\frac{(2n+1)\pi}{8}\\(C)\;\theta=\large\frac{n\pi}{2},\frac{(3n+1)\pi}{10}\\(D)\;\theta=\large\frac{\pi}{12},\frac{(2n+1)\pi}{12}\end{array} $

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