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The amount of $\;BaSO_{4}\;$ formed upon mixing 100 mL of $\;20.8\% BaCl_{2}\;$ solution with 50 mL of $\;9.8\%\;$ of $\;H_{2}SO_{4}\;$ solution will be : (Ba=137, Cl=35.5, S=32 ,H=1 and O=16)

$(a)\;23.3\;g \qquad(b)\;11.65\;g\qquad(c)\;30.6\;g\qquad(d)\;33.2\;g$

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