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Write the following set in the set-builder form $D=\{2,4,6.......\}$

$\begin{array}{1 1}(A)\;D=\{\text{x : x is an even natural number}\}\\(B)\;D=\{\text{x : x is an odd natural number}\}\\(C)\;D=\{\text{x : x is an integer}\}\\(D)\;\text{None of these}\end{array}$

D={ x: x is an even natural number }
Hence (A) is the correct answer.