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Match each of the set on the left in the roster form with the same set on the right described in set-builder form :

$\begin{array}{1 1}(i)\;\{1,2,3,6\}&(a)\;\{x : x is \;a\;prime \;number\; and\; a\; divisor\; of\; 6 \}\\(ii)\;\{2,3\}&(b)\;\{x : x \;is\; an\; odd\; natural \;number \;less\; than\; 10\} \\(iii)\;\{M,A,T,H,E,I,C,S\}&(c)\;\{x : x\; is\; natural\; number\; and\; divisor\; of\; 6\}\\(iv)\;\{1,3,5,7,9\}&(d)\;\{x : x \; is\; a\; letter\; of\; the\; word\; MATHEMATICS\}\end{array} $

$\begin{array}{1 1}(A)\;(i)-c,(ii)-a,(iii)-d,(iv)-b\\(B)\;(i)-a,(ii)-c,(iii)-b,(iv)-d\\(C)\;(i)-b,(ii)-a,(iii)-d,(iv)-c\\(D)\;(i)-c,(ii)-d,(iii)-a,(iv)-b\end{array} $

1 Answer

{1,2,3,6}-{x : x is natural number and divisor of 6}
{2,3}-{x : x is a prime number and a divisor of 6}
{M,A,T,H,E,I,C,S}-{x : x is a letter of the word MATHEMATICS}
{1,3,5,7,9}-{x : x is an odd natural number less than 10}
Hence (A) is the correct answer.
answered May 23, 2014 by sreemathi.v