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# Steel ruptures when a shear of $\;3.5 \times 10^{8}\;Nm^{-2}\;$ is applied .The force needed to punch a 1 cm diameter hole in a steel sheet 0.3 cm thick is nearly :

$(a)\;1.4 \times 10^{4}\;N \qquad(b)\;2.7 \times 10^{4}\;N \qquad(c)\;3.3 \times 10^{4}\;N \qquad(d)\;1.1 \times 10^{4}\;N$