$(a)\;l=\large\frac{2 n \lambda}{\sqrt{3}-1}\qquad(b)\;l=\large\frac{(2 n-1) \lambda}{2(\sqrt{3}-1)}\qquad(c)\;l=\large\frac{(2 n-1) \lambda \sqrt{3}}{4(2-\sqrt{3}}\qquad(d)\;l=\large\frac{(2 n-1) \lambda}{\sqrt{3}-1}$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...