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If a line L is perpendicular to the line $\;5x-y=1\;$ , and the area of the triangle formed by the line L and the coordinate axes is 5 , then the distance of line L from the line $\;x+5y=0\;$ is :

$(a)\;\large\frac{7}{\sqrt{5}}\qquad(b)\;\large\frac{5}{\sqrt{13}}\qquad(c)\;\large\frac{7}{\sqrt{13}}\qquad(d)\;\large\frac{5}{\sqrt{7}}$

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