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If the angle between the line $\;2(x+1)=y=z+4\;$ and the plane $\;2x-y+\sqrt{\lambda}z+4=0\;$ is $\;\large\frac{\pi}{6}\;$ ,then the value of $\;\lambda\;$ is :

$(a)\;\large\frac{135}{7}\qquad(b)\;\large\frac{45}{11}\qquad(c)\;\large\frac{45}{7}\qquad(d)\;\large\frac{135}{11}$

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