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# If m is non - zero number and $\;\int \large\frac{x^{5m-1}+2x^{4m-1}}{(x^{2m}+x^{m}+1)^{3}} \normalsize dx= \normalsize f(x)+c\;$ , then $\;\normalsize f(x)\;$ is :

$(a)\;\large\frac{x^{5m}}{2m(x^{2m}+x^{m}+1)^{2}}\qquad(b)\;\large\frac{x^{4m}}{2m(x^{2m}+x^{m}+1)^{2}}\qquad(c)\;\large\frac{2m(x^{5m}+x^{4m})}{(x^{2m}+x^{m}+1)^{2}}\qquad(d)\;\large\frac{(x^{5m}-x^{4m})}{2m(x^{2m}+x^{m}+1)^{2}}$