Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Ionization of energy of gaseous Na atoms is $\;495.5\;kJmol^{-1}\;$.The lowest possible frequency of light that ionizes a sodium atom is $\;(h=6.626 \times 10^{-34}\;Js\;N_{A}=6.022 \times 10^{23}\;mol^{-1})\; $

$(a)\;7.50 \times 10^{4}\;s^{-1}\qquad(b)\;4.76 \times 10^{14}\;s^{-1}\qquad(c)\;3.15 \times 10^{15}\;s^{-1}\qquad(d)\;1.24 \times 10^{15}\;s^{-1}$

Can you answer this question?

Please log in or register to answer this question.

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App