logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Zirconium phosphate $\;[Zr_{3}(PO_{4})_{4}]\;$ dissociates into three zirconium cations of charge +4 and four phosphate anions of charge -3 . If molar solubility of zirconium phosphate is denoted by S and its solubility product by $\;K_{sp}\;$ then which of the following relationship between $\;S\;$ and $\;K_{sp}\;$ is correct ?

$(a)\;\normalsize S=\{ \large\frac{K_{sp}}{(6912)^{\large\frac{1}{7}}}\}\qquad(b)\;\normalsize S=\{\large\frac{K_{sp}}{144}\}^{\large\frac{1}{7}}\qquad(c)\;\normalsize S=\{\large\frac{K_{sp}}{6912}\}^{\large\frac{1}{7}}\qquad(d)\;\normalsize S=\{\large\frac{K_{sp}}{144}\}^{7}$

Can you answer this question?
 
 

Please log in or register to answer this question.

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...