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# Write the following intervals in set-builder form (i) (-3,0)

$\begin{array}{1 1}(A)\;\{x : x \in R,-3 < x< 0\}\\(B)\;\{x : x \in R,-2 < x< 0\}\\(C)\;\{x : x \in R,-3 < x< 3\}\\(D)\;\text{None of these}\end{array}$

$\{x : x \in R,-3 < x< 0\}$
Hence (A) is the correct answer.