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# If $A=\{3,5,7,9,11\},B=\{7,9,11,13\},C=\{11,13,15\}$ and $D=\{15,17\}$.Find $A\cap B$

$\begin{array}{1 1}(A)\;\{3,5,7,9,11\}&(B)\;\{7,9,11,13\}\\(C)\;\{7,9\}&(D)\;\{3,5,7,9,11,13\}\end{array}$

A={3,5,7,9,11}
B={7,9,11,13}
Here 7,9 are the only common element in both A and B
$\therefore A\cap B=${3,5,7,9,11}$\cap${7,9,11,13}
$\Rightarrow${7,9}
Hence (C) is the correct answer.