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If $A=\{3,5,7,9,11\},B=\{7,9,11,13\},C=\{11,13,15\}$ and $D=\{15,17\}$.Find $B\cap C$

$\begin{array}{1 1}(A)\;\{11,13\}&(B)\;\{7,9,11,13\}\\(C)\;\{11,13,15\}&(D)\;\phi\end{array}$

$B=\{7,9,11,13\}$
$C=\{11,13,15\}$
Here 11,13 are the only common elements in both B & C
$\therefore B \cap C=\{7,9,11,13\} \cap \{11,13,15\}$
$\therefore \{11,13\}$
Hence (A) is the correct answer.