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# If $A=\{3,5,7,9,11\},B=\{7,9,11,13\},C=\{11,13,15\}$ and $D=\{15,17\}$.Find (iv) $A\cap C$

$\begin{array}{1 1}(A)\;\{3,5,7,9,11\}&(B)\;\{11,13,15\}\\(C)\;\phi&(D)\;\{11\}\end{array}$

$A=\{3,5,7,9,11\}$
$C=\{11,13,15\}$
Here 11 is the only element is common to $A$ & $C$
$\therefore A\cap C=\{3,5,7,9,11\} \cap \{11,13,15\}$
$\Rightarrow \{11\}$
Hence (D) is the correct answer.