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If $A=\{3,5,7,9,11\},B=\{7,9,11,13\},C=\{11,13,15\}$ and $D=\{15,17\}$.Find $A\cap D$

$\begin{array}{1 1}(A)\;\phi&(B)\;\{3,5,7,9,11\}\\(C)\;\{15,17\}&(D)\;\{3,5,7,9,11,15\}\end{array} $

1 Answer

$A=\{3,5,7,9,11\}$
$D=\{15,17\}$
$A\cap D$
Here there is no common element in both A & D
$\therefore A\cap D=\phi$
Hence (A) is the correct answer.
answered May 27, 2014 by sreemathi.v
 
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