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# If A={x : x is a natural number},B={x : x is an even natural number},C={x : x is an odd natural number } and D={x : x is a prime number },Find (i) $A\cap B$

$\begin{array}{1 1}(A)\;\{1,2,3,4,5.....\}&(B)\;\{2,4,6,8....\}\\(C)\;\phi&(D)\;\{2,3,4,5....\}\end{array}$

$A=\{1,2,3,4,5..\}$
$B=\{2,4,6,8...\}$
$\therefore$ Here all natural even numbers are common elements in both A and B
$\therefore A\cap B=\{2,4,6,8...\}$
Hence (B) is the correct answer.