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If A={x : x is a natural number},B={x : x is an even natural number},C={x : x is an odd natural number } and D={x : x is a prime number },Find (ii) $A\cap C$

$\begin{array}{1 1}(A)\;\{1,2,3,4,5,6....\}&(B)\;\phi\\(C)\;\{1,3,5,7....\}&(D)\;\{\phi\}\end{array}$

$A=\{1,2,3,4,5,6...\}$
$C=\{1,3,5,7...\}$
Here all natural odd numbers are common elements in both A and C
$A\cap C=\{1,2,3,4,5,6...\}\cap \{1,3,5,7...\}$
$\Rightarrow \{1,3,5,7...\}$
Hence (C) is the correct answer.