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If A={x : x is a natural number},B={x : x is an even natural number},C={x : x is an odd natural number } and D={x : x is a prime number },Find (iii) $A\cap D$

$\begin{array}{1 1}(A)\;\{1,2,3,4,5....\}&(B)\;\{1,3,5,7.......\}\\(C)\;\{2,3,5,7,11.....\}&(D)\;\{2,4,6,8.....\}\end{array} $

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1 Answer

$A=\{1,2,3,4,5...\}$
$D=\{2,3,5,7,11...\}$
$A\cap D=\{1,2,3,4,5...\}\cap \{2,3,5,7,11.....\}$
$\Rightarrow \{2,3,5,7,11....\}$
Here all prime numbers are common elements in both A & D
Hence (C) is the correct answer.
answered May 27, 2014 by sreemathi.v
 

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