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# If A={3,6,9,12,15,18,21},B={4,8,12,16,20},C={2,4,6,8,10,12,14,16},D={5,10,15,20} (xii) D-C

$\begin{array}{1 1}(A)\;\{5,10,15,20\}&(B)\;\{2,4,6,8,10,12,14,16\}\\(C)\;\{5,15,20\}&(D)\;\{2,4,6,8,12,14,16\}\end{array}$

C={2,4,6,8,10,12,14,16},D={5,10,15,20}
Here 10 is the only element in both the set D & C
$D-C=\{5,10,15,20\}-\{2,4,6,8,10,12,14,16\}$
$\Rightarrow \{5,15,20\}$
Hence (C) is the correct answer.
answered May 27, 2014