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A compound made up of A and B atoms have a crystalline structure, in which A forms Hexagonal close packed structure and B occupies $\large\frac{2}{3}$ of octahedral holes.What will be the simplest molecular formula?

$\begin{array}{1 1}(A)\;AB_3&(B)\;A_3B_2\\(C)\;A_6B_3&(D)\;\text{None of these}\end{array} $

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Effective number of A atoms forming HCP = 6
Effective number of octahedral holes in HCP = 6
So molecular formula will $A_6B_{\large\frac{6\times 2}{3}}=A_6B_4=A_3B_2$
Hence (B) is the correct answer.
answered May 28, 2014 by sreemathi.v

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